[GAP Forum] How to build an algorithm that returns groups with exp (G ') = 2.

[Stephen Linton]

Dear GAP Forum:

On 24 Jan 2012, at 14:03, Joy F. wrote:

> 
> I want to build an algorithm that returns all groups of order 32, which satisfy exp (G ') = exp (G / G) = 2.
> I can do testing group by group, the more I want to go with all groups of order 32, and my algorithm returns a list of groups satisfying the above properties.

The list of all groups of order 32 can be obtained via the AllGroups function. You can then select the groups you want using Filtered.

	Steve Linton